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201100311403 = 1618712423569
BaseRepresentation
bin1011101101001010000…
…0110011101101101011
3201020002000201021222121
42323102200303231223
511243323134431103
6232214553332111
720346311304655
oct2732240635553
9636060637877
10201100311403
1178316979472
1232b84107037
1315c6b27b804
149a3a2a16d5
15536ed6c6bd
hex2ed2833b6b

201100311403 has 4 divisors (see below), whose sum is σ = 201112751160. Its totient is φ = 201087871648.

The previous prime is 201100311323. The next prime is 201100311409. The reversal of 201100311403 is 304113001102.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304113001102 = 2152056500551.

It is a cyclic number.

It is not a de Polignac number, because 201100311403 - 217 = 201100180331 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201100311409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6195598 + ... + 6227971.

It is an arithmetic number, because the mean of its divisors is an integer number (50278187790).

Almost surely, 2201100311403 is an apocalyptic number.

201100311403 is a deficient number, since it is larger than the sum of its proper divisors (12439757).

201100311403 is a wasteful number, since it uses less digits than its factorization.

201100311403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12439756.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 201100311403 its reverse (304113001102), we get a palindrome (505213312505).

The spelling of 201100311403 in words is "two hundred one billion, one hundred million, three hundred eleven thousand, four hundred three".

Divisors: 1 16187 12423569 201100311403