Base | Representation |
---|---|
bin | 11101010000111001100… |
… | …010010110100011101100 |
3 | 21010020202202002212011210 |
4 | 131100321202112203230 |
5 | 230422022030014012 |
6 | 4135502323314420 |
7 | 265201462653516 |
oct | 35207142264354 |
9 | 7106682085153 |
10 | 2011010001132 |
11 | 70595679a680 |
12 | 2858b721ba10 |
13 | 117839580c42 |
14 | 6d494c04bb6 |
15 | 3749e89523c |
hex | 1d4398968ec |
2011010001132 has 48 divisors (see below), whose sum is σ = 5124142340352. Its totient is φ = 608776994880.
The previous prime is 2011010001083. The next prime is 2011010001149. The reversal of 2011010001132 is 2311000101102.
It is a super-2 number, since 2×20110100011322 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7619443 + ... + 7878954.
It is an arithmetic number, because the mean of its divisors is an integer number (106752965424).
Almost surely, 22011010001132 is an apocalyptic number.
2011010001132 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is an amenable number.
2011010001132 is an abundant number, since it is smaller than the sum of its proper divisors (3113132339220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2011010001132 is a wasteful number, since it uses less digits than its factorization.
2011010001132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15499398 (or 15499396 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 12.
Adding to 2011010001132 its reverse (2311000101102), we get a palindrome (4322010102234).
The spelling of 2011010001132 in words is "two trillion, eleven billion, ten million, one thousand, one hundred thirty-two".
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