Base | Representation |
---|---|
bin | 11101010000111001100… |
… | …010011011011101010011 |
3 | 21010020202202010212201011 |
4 | 131100321202123131103 |
5 | 230422022031134303 |
6 | 4135502323551351 |
7 | 265201463066161 |
oct | 35207142333523 |
9 | 7106682125634 |
10 | 2011010021203 |
11 | 705956803767 |
12 | 2858b722b557 |
13 | 11783958a111 |
14 | 6d494c0c231 |
15 | 3749e89b16d |
hex | 1d43989b753 |
2011010021203 has 2 divisors, whose sum is σ = 2011010021204. Its totient is φ = 2011010021202.
The previous prime is 2011010021197. The next prime is 2011010021213. The reversal of 2011010021203 is 3021200101102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011010021203 - 25 = 2011010021171 is a prime.
It is a super-2 number, since 2×20110100212032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2011010021213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005505010601 + 1005505010602.
It is an arithmetic number, because the mean of its divisors is an integer number (1005505010602).
Almost surely, 22011010021203 is an apocalyptic number.
2011010021203 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011010021203 is an equidigital number, since it uses as much as digits as its factorization.
2011010021203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 2011010021203 its reverse (3021200101102), we get a palindrome (5032210122305).
The spelling of 2011010021203 in words is "two trillion, eleven billion, ten million, twenty-one thousand, two hundred three".
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