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2011020113 is a prime number
BaseRepresentation
bin111011111011101…
…1011101101010001
312012011002101222102
41313313123231101
513104310120423
6531315050145
7100556250254
oct16767335521
95164071872
102011020113
119421941a3
124815a0955
1326083533b
1415112709b
15bb83cc28
hex77ddbb51

2011020113 has 2 divisors, whose sum is σ = 2011020114. Its totient is φ = 2011020112.

The previous prime is 2011020061. The next prime is 2011020139. The reversal of 2011020113 is 3110201102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1194946624 + 816073489 = 34568^2 + 28567^2 .

It is a cyclic number.

It is not a de Polignac number, because 2011020113 - 216 = 2010954577 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2011020094 and 2011020103.

It is not a weakly prime, because it can be changed into another prime (2011026113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005510056 + 1005510057.

It is an arithmetic number, because the mean of its divisors is an integer number (1005510057).

Almost surely, 22011020113 is an apocalyptic number.

It is an amenable number.

2011020113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011020113 is an equidigital number, since it uses as much as digits as its factorization.

2011020113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 2011020113 is about 44844.3989033190. The cubic root of 2011020113 is about 1262.2308913465.

Adding to 2011020113 its reverse (3110201102), we get a palindrome (5121221215).

The spelling of 2011020113 in words is "two billion, eleven million, twenty thousand, one hundred thirteen".