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2011020202101 = 3670340067367
BaseRepresentation
bin11101010000111010001…
…001010001000001110101
321010020210110022010021110
4131100322021101001311
5230422032132431401
64135503330105233
7265201645451121
oct35207211210165
97106713263243
102011020202101
11705961527829
122858ba71b219
1311783b713111
146d4962dc581
15374a070c9d6
hex1d43a251075

2011020202101 has 4 divisors (see below), whose sum is σ = 2681360269472. Its totient is φ = 1340680134732.

The previous prime is 2011020202097. The next prime is 2011020202109. The reversal of 2011020202101 is 1012020201102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2011020202101 - 22 = 2011020202097 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2011020202109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335170033681 + ... + 335170033686.

It is an arithmetic number, because the mean of its divisors is an integer number (670340067368).

Almost surely, 22011020202101 is an apocalyptic number.

It is an amenable number.

2011020202101 is a deficient number, since it is larger than the sum of its proper divisors (670340067371).

2011020202101 is an equidigital number, since it uses as much as digits as its factorization.

2011020202101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 670340067370.

The product of its (nonzero) digits is 16, while the sum is 12.

Adding to 2011020202101 its reverse (1012020201102), we get a palindrome (3023040403203).

Subtracting from 2011020202101 its reverse (1012020201102), we obtain a palindrome (999000000999).

The spelling of 2011020202101 in words is "two trillion, eleven billion, twenty million, two hundred two thousand, one hundred one".

Divisors: 1 3 670340067367 2011020202101