Base | Representation |
---|---|
bin | 101101101110011010111011… |
… | …010110101001110100001011 |
3 | 222101001011200021000001111212 |
4 | 231232122323112221310023 |
5 | 202324324101103324042 |
6 | 1551413010312243335 |
7 | 60234101362663451 |
oct | 5556327326516413 |
9 | 871034607001455 |
10 | 201102102011147 |
11 | 59093a16956437 |
12 | 1a67ab270a054b |
13 | 8829b016aa51c |
14 | 379357233c9d1 |
15 | 183b1d9353482 |
hex | b6e6bb5a9d0b |
201102102011147 has 2 divisors, whose sum is σ = 201102102011148. Its totient is φ = 201102102011146.
The previous prime is 201102102011143. The next prime is 201102102011263. The reversal of 201102102011147 is 741110201201102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201102102011147 - 22 = 201102102011143 is a prime.
It is a super-2 number, since 2×2011021020111472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201102102011143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100551051005573 + 100551051005574.
It is an arithmetic number, because the mean of its divisors is an integer number (100551051005574).
Almost surely, 2201102102011147 is an apocalyptic number.
201102102011147 is a deficient number, since it is larger than the sum of its proper divisors (1).
201102102011147 is an equidigital number, since it uses as much as digits as its factorization.
201102102011147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 201102102011147 its reverse (741110201201102), we get a palindrome (942212303212249).
The spelling of 201102102011147 in words is "two hundred one trillion, one hundred two billion, one hundred two million, eleven thousand, one hundred forty-seven".
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