Base | Representation |
---|---|
bin | 11101010000111010001… |
… | …101000100101001010111 |
3 | 21010020210112011211002011 |
4 | 131100322031010221113 |
5 | 230422032411344314 |
6 | 4135503403325051 |
7 | 265201660105252 |
oct | 35207215045127 |
9 | 7106715154064 |
10 | 2011021199959 |
11 | 705962049502 |
12 | 2858bab20787 |
13 | 11783b9a2375 |
14 | 6d4964bc099 |
15 | 374a08584c4 |
hex | 1d43a344a57 |
2011021199959 has 2 divisors, whose sum is σ = 2011021199960. Its totient is φ = 2011021199958.
The previous prime is 2011021199927. The next prime is 2011021200011. The reversal of 2011021199959 is 9599911201102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011021199959 - 25 = 2011021199927 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011021199459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005510599979 + 1005510599980.
It is an arithmetic number, because the mean of its divisors is an integer number (1005510599980).
Almost surely, 22011021199959 is an apocalyptic number.
2011021199959 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011021199959 is an equidigital number, since it uses as much as digits as its factorization.
2011021199959 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 131220, while the sum is 49.
The spelling of 2011021199959 in words is "two trillion, eleven billion, twenty-one million, one hundred ninety-nine thousand, nine hundred fifty-nine".
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