Base | Representation |
---|---|
bin | 1001001001010010001111… |
… | …10110011100010101010011 |
3 | 2122012112001100212022211110 |
4 | 10210221013312130111103 |
5 | 10113441234014142120 |
6 | 110434303501544403 |
7 | 4143626360265360 |
oct | 444510766342523 |
9 | 78175040768743 |
10 | 20110242334035 |
11 | 6453784585307 |
12 | 23095bb575103 |
13 | b2b506a6ac59 |
14 | 4d74ab6c3467 |
15 | 24d1a839b2e0 |
hex | 124a47d9c553 |
20110242334035 has 16 divisors (see below), whose sum is σ = 36773014553856. Its totient is φ = 9193253638368.
The previous prime is 20110242334033. The next prime is 20110242334069. The reversal of 20110242334035 is 53043324201102.
It is not a de Polignac number, because 20110242334035 - 21 = 20110242334033 is a prime.
It is a super-2 number, since 2×201102423340352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20110242333993 and 20110242334011.
It is not an unprimeable number, because it can be changed into a prime (20110242334033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 95763058629 + ... + 95763058838.
It is an arithmetic number, because the mean of its divisors is an integer number (2298313409616).
Almost surely, 220110242334035 is an apocalyptic number.
20110242334035 is a deficient number, since it is larger than the sum of its proper divisors (16662772219821).
20110242334035 is a wasteful number, since it uses less digits than its factorization.
20110242334035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 191526117482.
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 20110242334035 its reverse (53043324201102), we get a palindrome (73153566535137).
The spelling of 20110242334035 in words is "twenty trillion, one hundred ten billion, two hundred forty-two million, three hundred thirty-four thousand, thirty-five".
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