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20110341021 = 36703447007
BaseRepresentation
bin10010101110101010…
…110111001110011101
31220220112011011200020
4102232222313032131
5312141221403041
613123310222353
71311232035561
oct225652671635
956815134606
1020110341021
11858a843951
123a92ab49b9
131b864cc294
14d8ac096a1
157ca7b4866
hex4aeab739d

20110341021 has 4 divisors (see below), whose sum is σ = 26813788032. Its totient is φ = 13406894012.

The previous prime is 20110340963. The next prime is 20110341023. The reversal of 20110341021 is 12014301102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20110341021 - 213 = 20110332829 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20110341023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3351723501 + ... + 3351723506.

It is an arithmetic number, because the mean of its divisors is an integer number (6703447008).

Almost surely, 220110341021 is an apocalyptic number.

It is an amenable number.

20110341021 is a deficient number, since it is larger than the sum of its proper divisors (6703447011).

20110341021 is an equidigital number, since it uses as much as digits as its factorization.

20110341021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6703447010.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 20110341021 its reverse (12014301102), we get a palindrome (32124642123).

The spelling of 20110341021 in words is "twenty billion, one hundred ten million, three hundred forty-one thousand, twenty-one".

Divisors: 1 3 6703447007 20110341021