Base | Representation |
---|---|
bin | 101101101110100010011110… |
… | …101100110010110000001101 |
3 | 222101001221121101220001102111 |
4 | 231232202132230302300031 |
5 | 202324442203032212003 |
6 | 1551420431112424021 |
7 | 60234506341021402 |
oct | 5556423654626015 |
9 | 871057541801374 |
10 | 201110211210253 |
11 | 590973a8328784 |
12 | 1a68060a9a8011 |
13 | 882a7c47352a7 |
14 | 3793b013102a9 |
15 | 183b51121de6d |
hex | b6e89eb32c0d |
201110211210253 has 2 divisors, whose sum is σ = 201110211210254. Its totient is φ = 201110211210252.
The previous prime is 201110211210211. The next prime is 201110211210283. The reversal of 201110211210253 is 352012112011102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 107116662679524 + 93993548530729 = 10349718^2 + 9695027^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201110211210253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201110211210283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100555105605126 + 100555105605127.
It is an arithmetic number, because the mean of its divisors is an integer number (100555105605127).
Almost surely, 2201110211210253 is an apocalyptic number.
It is an amenable number.
201110211210253 is a deficient number, since it is larger than the sum of its proper divisors (1).
201110211210253 is an equidigital number, since it uses as much as digits as its factorization.
201110211210253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 201110211210253 its reverse (352012112011102), we get a palindrome (553122323221355).
The spelling of 201110211210253 in words is "two hundred one trillion, one hundred ten billion, two hundred eleven million, two hundred ten thousand, two hundred fifty-three".
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