Base | Representation |
---|---|
bin | 1001001001010011101100… |
… | …10001100111110110000011 |
3 | 2122012121001122110101011212 |
4 | 10210221312101213312003 |
5 | 10113444332412223021 |
6 | 110434513044000335 |
7 | 4143654565524623 |
oct | 444516621476603 |
9 | 78177048411155 |
10 | 20111021211011 |
11 | 64540441a9095 |
12 | 23097983900ab |
13 | b2b5cc2364c3 |
14 | 4d7542d10883 |
15 | 24d20194e85b |
hex | 124a76467d83 |
20111021211011 has 2 divisors, whose sum is σ = 20111021211012. Its totient is φ = 20111021211010.
The previous prime is 20111021210999. The next prime is 20111021211059. The reversal of 20111021211011 is 11011212011102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20111021211011 - 218 = 20111020948867 is a prime.
It is not a weakly prime, because it can be changed into another prime (20111021241011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055510605505 + 10055510605506.
It is an arithmetic number, because the mean of its divisors is an integer number (10055510605506).
Almost surely, 220111021211011 is an apocalyptic number.
20111021211011 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111021211011 is an equidigital number, since it uses as much as digits as its factorization.
20111021211011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 20111021211011 its reverse (11011212011102), we get a palindrome (31122233222113).
The spelling of 20111021211011 in words is "twenty trillion, one hundred eleven billion, twenty-one million, two hundred eleven thousand, eleven".
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