Base | Representation |
---|---|
bin | 1001001001010011110111… |
… | …00100010100110111001001 |
3 | 2122012121021211112022212122 |
4 | 10210221323210110313021 |
5 | 10114000023130000243 |
6 | 110434525535021025 |
7 | 4143660024315101 |
oct | 444517344246711 |
9 | 78177254468778 |
10 | 20111110000073 |
11 | 645408a332684 |
12 | 230980206a775 |
13 | b2b614753201 |
14 | 4d7550a24201 |
15 | 24d20963c668 |
hex | 124a7b914dc9 |
20111110000073 has 2 divisors, whose sum is σ = 20111110000074. Its totient is φ = 20111110000072.
The previous prime is 20111110000067. The next prime is 20111110000133. The reversal of 20111110000073 is 37000001111102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19301014597264 + 810095402809 = 4393292^2 + 900053^2 .
It is a cyclic number.
It is not a de Polignac number, because 20111110000073 - 214 = 20111109983689 is a prime.
It is not a weakly prime, because it can be changed into another prime (20111110005073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055555000036 + 10055555000037.
It is an arithmetic number, because the mean of its divisors is an integer number (10055555000037).
Almost surely, 220111110000073 is an apocalyptic number.
It is an amenable number.
20111110000073 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111110000073 is an equidigital number, since it uses as much as digits as its factorization.
20111110000073 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 17.
Adding to 20111110000073 its reverse (37000001111102), we get a palindrome (57111111111175).
The spelling of 20111110000073 in words is "twenty trillion, one hundred eleven billion, one hundred ten million, seventy-three", and thus it is an aban number.
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