Base | Representation |
---|---|
bin | 11101010000111111100… |
… | …100000101110010001101 |
3 | 21010021000210101020012112 |
4 | 131100333210011302031 |
5 | 230422223421320023 |
6 | 4135520334513405 |
7 | 265204131315662 |
oct | 35207744056215 |
9 | 7107023336175 |
10 | 2011111120013 |
11 | 7059a88857a6 |
12 | 285925065865 |
13 | 1178544c6ab8 |
14 | 6d4a4407a69 |
15 | 374a86bb478 |
hex | 1d43f905c8d |
2011111120013 has 2 divisors, whose sum is σ = 2011111120014. Its totient is φ = 2011111120012.
The previous prime is 2011111120009. The next prime is 2011111120033. The reversal of 2011111120013 is 3100211111102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1548924615364 + 462186504649 = 1244558^2 + 679843^2 .
It is a cyclic number.
It is not a de Polignac number, because 2011111120013 - 22 = 2011111120009 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2011111120013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011111120033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005555560006 + 1005555560007.
It is an arithmetic number, because the mean of its divisors is an integer number (1005555560007).
Almost surely, 22011111120013 is an apocalyptic number.
It is an amenable number.
2011111120013 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011111120013 is an equidigital number, since it uses as much as digits as its factorization.
2011111120013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 2011111120013 its reverse (3100211111102), we get a palindrome (5111322231115).
The spelling of 2011111120013 in words is "two trillion, eleven billion, one hundred eleven million, one hundred twenty thousand, thirteen".
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