Base | Representation |
---|---|
bin | 11101010000111111100… |
… | …100100000111101100011 |
3 | 21010021000210120212220102 |
4 | 131100333210200331203 |
5 | 230422223433400311 |
6 | 4135520341133015 |
7 | 265204132261346 |
oct | 35207744407543 |
9 | 7107023525812 |
10 | 2011111231331 |
11 | 7059a89513a4 |
12 | 2859250ba16b |
13 | 117854535677 |
14 | 6d4a443645d |
15 | 374a86de43b |
hex | 1d43f920f63 |
2011111231331 has 2 divisors, whose sum is σ = 2011111231332. Its totient is φ = 2011111231330.
The previous prime is 2011111231313. The next prime is 2011111231333. The reversal of 2011111231331 is 1331321111102.
Together with previous prime (2011111231313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2011111231331 - 214 = 2011111214947 is a prime.
It is a super-2 number, since 2×20111112313312 (a number of 25 digits) contains 22 as substring.
Together with 2011111231333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2011111231333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005555615665 + 1005555615666.
It is an arithmetic number, because the mean of its divisors is an integer number (1005555615666).
Almost surely, 22011111231331 is an apocalyptic number.
2011111231331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011111231331 is an equidigital number, since it uses as much as digits as its factorization.
2011111231331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 2011111231331 its reverse (1331321111102), we get a palindrome (3342432342433).
The spelling of 2011111231331 in words is "two trillion, eleven billion, one hundred eleven million, two hundred thirty-one thousand, three hundred thirty-one".
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