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20111135003 is a prime number
BaseRepresentation
bin10010101110101101…
…111001000100011011
31220220120122111210222
4102232231321010123
5312141422310003
613123335230255
71311241553441
oct225655710433
956816574728
1020111135003
118590236433
123a9321838b
131b867197ab
14d8ad74b91
157ca8bec38
hex4aeb7911b

20111135003 has 2 divisors, whose sum is σ = 20111135004. Its totient is φ = 20111135002.

The previous prime is 20111134951. The next prime is 20111135047. The reversal of 20111135003 is 30053111102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20111135003 - 226 = 20044026139 is a prime.

It is a super-2 number, since 2×201111350032 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20111135063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055567501 + 10055567502.

It is an arithmetic number, because the mean of its divisors is an integer number (10055567502).

Almost surely, 220111135003 is an apocalyptic number.

20111135003 is a deficient number, since it is larger than the sum of its proper divisors (1).

20111135003 is an equidigital number, since it uses as much as digits as its factorization.

20111135003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 17.

Adding to 20111135003 its reverse (30053111102), we get a palindrome (50164246105).

The spelling of 20111135003 in words is "twenty billion, one hundred eleven million, one hundred thirty-five thousand, three".