Base | Representation |
---|---|
bin | 11101010001000000000… |
… | …110110001100010000111 |
3 | 21010021001102111011012121 |
4 | 131101000012301202013 |
5 | 230422233233241403 |
6 | 4135521301430411 |
7 | 265204301514352 |
oct | 35210006614207 |
9 | 7107042434177 |
10 | 2011120212103 |
11 | 705a02a25822 |
12 | 28592810b407 |
13 | 11785635b332 |
14 | 6d4a56d3299 |
15 | 374a93b53bd |
hex | 1d4401b1887 |
2011120212103 has 2 divisors, whose sum is σ = 2011120212104. Its totient is φ = 2011120212102.
The previous prime is 2011120211987. The next prime is 2011120212121. The reversal of 2011120212103 is 3012120211102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2011120212103 - 217 = 2011120081031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011120212403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005560106051 + 1005560106052.
It is an arithmetic number, because the mean of its divisors is an integer number (1005560106052).
Almost surely, 22011120212103 is an apocalyptic number.
2011120212103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011120212103 is an equidigital number, since it uses as much as digits as its factorization.
2011120212103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 2011120212103 its reverse (3012120211102), we get a palindrome (5023240423205).
The spelling of 2011120212103 in words is "two trillion, eleven billion, one hundred twenty million, two hundred twelve thousand, one hundred three".
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