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20111214503 is a prime number
BaseRepresentation
bin10010101110101110…
…001100011110100111
31220220120210112212102
4102232232030132213
5312141432331003
613123341042315
71311242334302
oct225656143647
956816715772
1020111214503
118590290136
123a9325639b
131b86746a33
14d8ad95b39
157ca8d8588
hex4aeb8c7a7

20111214503 has 2 divisors, whose sum is σ = 20111214504. Its totient is φ = 20111214502.

The previous prime is 20111214463. The next prime is 20111214511. The reversal of 20111214503 is 30541211102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20111214503 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20111214103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055607251 + 10055607252.

It is an arithmetic number, because the mean of its divisors is an integer number (10055607252).

Almost surely, 220111214503 is an apocalyptic number.

20111214503 is a deficient number, since it is larger than the sum of its proper divisors (1).

20111214503 is an equidigital number, since it uses as much as digits as its factorization.

20111214503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 20111214503 its reverse (30541211102), we get a palindrome (50652425605).

The spelling of 20111214503 in words is "twenty billion, one hundred eleven million, two hundred fourteen thousand, five hundred three".