Base | Representation |
---|---|
bin | 10010101110101110… |
… | …001100011110100111 |
3 | 1220220120210112212102 |
4 | 102232232030132213 |
5 | 312141432331003 |
6 | 13123341042315 |
7 | 1311242334302 |
oct | 225656143647 |
9 | 56816715772 |
10 | 20111214503 |
11 | 8590290136 |
12 | 3a9325639b |
13 | 1b86746a33 |
14 | d8ad95b39 |
15 | 7ca8d8588 |
hex | 4aeb8c7a7 |
20111214503 has 2 divisors, whose sum is σ = 20111214504. Its totient is φ = 20111214502.
The previous prime is 20111214463. The next prime is 20111214511. The reversal of 20111214503 is 30541211102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20111214503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20111214103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055607251 + 10055607252.
It is an arithmetic number, because the mean of its divisors is an integer number (10055607252).
Almost surely, 220111214503 is an apocalyptic number.
20111214503 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111214503 is an equidigital number, since it uses as much as digits as its factorization.
20111214503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 20111214503 its reverse (30541211102), we get a palindrome (50652425605).
The spelling of 20111214503 in words is "twenty billion, one hundred eleven million, two hundred fourteen thousand, five hundred three".
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