Base | Representation |
---|---|
bin | 1001001001010100000100… |
… | …01000011001100111000111 |
3 | 2122012121120111202000000201 |
4 | 10210222002020121213013 |
5 | 10114000234322320012 |
6 | 110434544511151331 |
7 | 4143662532316342 |
oct | 444520210314707 |
9 | 78177514660021 |
10 | 20111220120007 |
11 | 6454136506395 |
12 | 2309832b15547 |
13 | b2b6314cb033 |
14 | 4d75614cb459 |
15 | 24d214140857 |
hex | 124a822199c7 |
20111220120007 has 2 divisors, whose sum is σ = 20111220120008. Its totient is φ = 20111220120006.
The previous prime is 20111220119951. The next prime is 20111220120011. The reversal of 20111220120007 is 70002102211102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20111220120007 is a prime.
It is a super-2 number, since 2×201112201200072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20111220190007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055610060003 + 10055610060004.
It is an arithmetic number, because the mean of its divisors is an integer number (10055610060004).
Almost surely, 220111220120007 is an apocalyptic number.
20111220120007 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111220120007 is an equidigital number, since it uses as much as digits as its factorization.
20111220120007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 20111220120007 its reverse (70002102211102), we get a palindrome (90113322331109).
The spelling of 20111220120007 in words is "twenty trillion, one hundred eleven billion, two hundred twenty million, one hundred twenty thousand, seven".
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