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20111221220141 is a prime number
BaseRepresentation
bin1001001001010100000100…
…01100100110001100101101
32122012121120120210220010102
410210222002030212030231
510114000240113021031
6110434544550520445
74143662544550622
oct444520214461455
978177516726112
1020111221220141
116454137097997
122309833366125
13b2b6317c49bc
144d75616d6349
1524d2142ab7cb
hex124a8232632d

20111221220141 has 2 divisors, whose sum is σ = 20111221220142. Its totient is φ = 20111221220140.

The previous prime is 20111221220023. The next prime is 20111221220149. The reversal of 20111221220141 is 14102212211102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10528915239241 + 9582305980900 = 3244829^2 + 3095530^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20111221220141 is a prime.

It is a super-2 number, since 2×201112212201412 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20111221220149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055610610070 + 10055610610071.

It is an arithmetic number, because the mean of its divisors is an integer number (10055610610071).

Almost surely, 220111221220141 is an apocalyptic number.

It is an amenable number.

20111221220141 is a deficient number, since it is larger than the sum of its proper divisors (1).

20111221220141 is an equidigital number, since it uses as much as digits as its factorization.

20111221220141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 20111221220141 its reverse (14102212211102), we get a palindrome (34213433431243).

The spelling of 20111221220141 in words is "twenty trillion, one hundred eleven billion, two hundred twenty-one million, two hundred twenty thousand, one hundred forty-one".