Base | Representation |
---|---|
bin | 11101010001000000010… |
… | …101010100000000100011 |
3 | 21010021001200122210020012 |
4 | 131101000111110000203 |
5 | 230422240222221311 |
6 | 4135521515235135 |
7 | 265204346066663 |
oct | 35210025240043 |
9 | 7107050583205 |
10 | 2011124023331 |
11 | 705a050991a5 |
12 | 285929448aab |
13 | 117857093cb7 |
14 | 6d4a60061a3 |
15 | 374a98b978b |
hex | 1d440554023 |
2011124023331 has 2 divisors, whose sum is σ = 2011124023332. Its totient is φ = 2011124023330.
The previous prime is 2011124023319. The next prime is 2011124023387. The reversal of 2011124023331 is 1333204211102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2011124023331 is a prime.
It is a super-2 number, since 2×20111240233312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2011124023297 and 2011124023306.
It is not a weakly prime, because it can be changed into another prime (2011124623331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005562011665 + 1005562011666.
It is an arithmetic number, because the mean of its divisors is an integer number (1005562011666).
Almost surely, 22011124023331 is an apocalyptic number.
2011124023331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011124023331 is an equidigital number, since it uses as much as digits as its factorization.
2011124023331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 2011124023331 its reverse (1333204211102), we get a palindrome (3344328234433).
The spelling of 2011124023331 in words is "two trillion, eleven billion, one hundred twenty-four million, twenty-three thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •