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20111250400000 = 285531180833
BaseRepresentation
bin1001001001010100000111…
…11011111010001100000000
32122012121122121201101100221
410210222003323322030000
510114000320100300000
6110434551512152424
74143663350562244
oct444520373721400
978177577641327
1020111250400000
116454151608181
122309841098714
13b2b6378705a6
144d7565530424
1524d216b2261a
hex124a83efa300

20111250400000 has 216 divisors, whose sum is σ = 50338677680928. Its totient is φ = 8018534400000.

The previous prime is 20111250399997. The next prime is 20111250400013. The reversal of 20111250400000 is 405211102.

It is a super-3 number, since 3×201112504000003 (a number of 41 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 248759584 + ... + 248840416.

It is an arithmetic number, because the mean of its divisors is an integer number (233049433708).

Almost surely, 220111250400000 is an apocalyptic number.

20111250400000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20111250400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25169338840464).

20111250400000 is an abundant number, since it is smaller than the sum of its proper divisors (30227427280928).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20111250400000 is an frugal number, since it uses more digits than its factorization.

20111250400000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81185 (or 81151 counting only the distinct ones).

The product of its (nonzero) digits is 80, while the sum is 16.

Adding to 20111250400000 its reverse (405211102), we get a palindrome (20111655611102).

The spelling of 20111250400000 in words is "twenty trillion, one hundred eleven billion, two hundred fifty million, four hundred thousand".