201113100233 has 4 divisors (see below), whose sum is σ = 201114125328. Its totient is φ = 201112075140.

The previous prime is 201113100197. The next prime is 201113100271. The reversal of 201113100233 is 332001311102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 332001311102 = 2 ⋅166000655551.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-201113100233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201113102233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115991 + ... + 644732.

It is an arithmetic number, because the mean of its divisors is an integer number (50278531332).

Almost surely, 2^201113100233 is an apocalyptic number.

It is an amenable number.

201113100233 is a deficient number, since it is larger than the sum of its proper divisors (1025095).

201113100233 is an equidigital number, since it uses as much as digits as its factorization.

201113100233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1025094.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 201113100233 its reverse (332001311102), we get a palindrome (533114411335).

The spelling of 201113100233 in words is "two hundred one billion, one hundred thirteen million, one hundred thousand, two hundred thirty-three".