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20111331181 is a prime number
BaseRepresentation
bin10010101110101110…
…101000111101101101
31220220121000110220211
4102232232220331231
5312142000044211
613123343342421
71311243331414
oct225656507555
956817013824
1020111331181
11859035a867
123a932b1a11
131b86787b86
14d8adc647b
157ca90ce21
hex4aeba8f6d

20111331181 has 2 divisors, whose sum is σ = 20111331182. Its totient is φ = 20111331180.

The previous prime is 20111331113. The next prime is 20111331319. The reversal of 20111331181 is 18113311102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13244557225 + 6866773956 = 115085^2 + 82866^2 .

It is a cyclic number.

It is not a de Polignac number, because 20111331181 - 215 = 20111298413 is a prime.

It is a super-2 number, since 2×201113311812 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20111331101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055665590 + 10055665591.

It is an arithmetic number, because the mean of its divisors is an integer number (10055665591).

Almost surely, 220111331181 is an apocalyptic number.

It is an amenable number.

20111331181 is a deficient number, since it is larger than the sum of its proper divisors (1).

20111331181 is an equidigital number, since it uses as much as digits as its factorization.

20111331181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 22.

Adding to 20111331181 its reverse (18113311102), we get a palindrome (38224642283).

The spelling of 20111331181 in words is "twenty billion, one hundred eleven million, three hundred thirty-one thousand, one hundred eighty-one".