Base | Representation |
---|---|
bin | 1001001001010100010001… |
… | …10111000101000111011111 |
3 | 2122012121212101011220212122 |
4 | 10210222020313011013133 |
5 | 10114001002223121002 |
6 | 110435004023053155 |
7 | 4143665403050246 |
oct | 444521067050737 |
9 | 78177771156778 |
10 | 20111333020127 |
11 | 6454194208978 |
12 | 23098648a11bb |
13 | b2b64ba0a43b |
14 | 4d75724b995d |
15 | 24d21dee26a2 |
hex | 124a88dc51df |
20111333020127 has 2 divisors, whose sum is σ = 20111333020128. Its totient is φ = 20111333020126.
The previous prime is 20111333020099. The next prime is 20111333020187. The reversal of 20111333020127 is 72102033311102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20111333020127 - 28 = 20111333019871 is a prime.
It is a super-2 number, since 2×201113330201272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20111333020096 and 20111333020105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20111333020187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055666510063 + 10055666510064.
It is an arithmetic number, because the mean of its divisors is an integer number (10055666510064).
Almost surely, 220111333020127 is an apocalyptic number.
20111333020127 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111333020127 is an equidigital number, since it uses as much as digits as its factorization.
20111333020127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 20111333020127 its reverse (72102033311102), we get a palindrome (92213366331229).
The spelling of 20111333020127 in words is "twenty trillion, one hundred eleven billion, three hundred thirty-three million, twenty thousand, one hundred twenty-seven".
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