2011134244333 has 2 divisors, whose sum is σ = 2011134244334. Its totient is φ = 2011134244332.

The previous prime is 2011134244277. The next prime is 2011134244373. The reversal of 2011134244333 is 3334424311102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1491138938884 + 519995305449 = 1221122^2 + 721107^2 .

It is a cyclic number.

It is not a de Polignac number, because 2011134244333 - 2⁹ = 2011134243821 is a prime.

It is a super-2 number, since 2×2011134244333² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2011134244295 and 2011134244304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2011134244373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005567122166 + 1005567122167.

It is an arithmetic number, because the mean of its divisors is an integer number (1005567122167).

Almost surely, 2^{2011134244333} is an apocalyptic number.

It is an amenable number.

2011134244333 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011134244333 is an equidigital number, since it uses as much as digits as its factorization.

2011134244333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 2011134244333 its reverse (3334424311102), we get a palindrome (5345558555435).

The spelling of 2011134244333 in words is "two trillion, eleven billion, one hundred thirty-four million, two hundred forty-four thousand, three hundred thirty-three".