Base | Representation |
---|---|
bin | 1001001001010100011010… |
… | …11101100100110001101101 |
3 | 2122012122001202110002101102 |
4 | 10210222031131210301231 |
5 | 10114001132004021031 |
6 | 110435015421452445 |
7 | 4144000331202212 |
oct | 444521535446155 |
9 | 78178052402342 |
10 | 20111410220141 |
11 | 6454223847439 |
12 | 2309886711125 |
13 | b2b6619ca216 |
14 | 4d757c853b09 |
15 | 24d225b917cb |
hex | 124a8d764c6d |
20111410220141 has 2 divisors, whose sum is σ = 20111410220142. Its totient is φ = 20111410220140.
The previous prime is 20111410220093. The next prime is 20111410220227. The reversal of 20111410220141 is 14102201411102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18569290824100 + 1542119396041 = 4309210^2 + 1241821^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20111410220141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20111410225141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055705110070 + 10055705110071.
It is an arithmetic number, because the mean of its divisors is an integer number (10055705110071).
Almost surely, 220111410220141 is an apocalyptic number.
It is an amenable number.
20111410220141 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111410220141 is an equidigital number, since it uses as much as digits as its factorization.
20111410220141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 20.
Adding to 20111410220141 its reverse (14102201411102), we get a palindrome (34213611631243).
The spelling of 20111410220141 in words is "twenty trillion, one hundred eleven billion, four hundred ten million, two hundred twenty thousand, one hundred forty-one".
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