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2011151112150 = 2352294169116319
BaseRepresentation
bin11101010001000001111…
…100101001011111010110
321010021010120122001002210
4131101001330221133112
5230422314141042100
64135524324014250
7265205125252065
oct35210174513726
97107116561083
102011151112150
11705a19410454
12285936531386
1311785c889b9b
146d4a98581dc
15374abe6ac50
hex1d441f297d6

2011151112150 has 192 divisors, whose sum is σ = 5293461196800. Its totient is φ = 504422016000.

The previous prime is 2011151112119. The next prime is 2011151112163. The reversal of 2011151112150 is 512111511102.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 123231691 + ... + 123248009.

It is an arithmetic number, because the mean of its divisors is an integer number (27570110400).

Almost surely, 22011151112150 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2011151112150, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2646730598400).

2011151112150 is an abundant number, since it is smaller than the sum of its proper divisors (3282310084650).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2011151112150 is a wasteful number, since it uses less digits than its factorization.

2011151112150 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17095 (or 17090 counting only the distinct ones).

The product of its (nonzero) digits is 100, while the sum is 21.

Adding to 2011151112150 its reverse (512111511102), we get a palindrome (2523262623252).

The spelling of 2011151112150 in words is "two trillion, eleven billion, one hundred fifty-one million, one hundred twelve thousand, one hundred fifty".