Base | Representation |
---|---|
bin | 1001001001010101100010… |
… | …10010111001001101000011 |
3 | 2122012200121122200012010020 |
4 | 10210222301102321031003 |
5 | 10114003344404300003 |
6 | 110435155215104523 |
7 | 4144021251144165 |
oct | 444526122711503 |
9 | 78180548605106 |
10 | 20112011400003 |
11 | 64545021307a6 |
12 | 2309a13b12143 |
13 | b2b729419b53 |
14 | 4d75d8626935 |
15 | 24d25d843d53 |
hex | 124ab14b9343 |
20112011400003 has 8 divisors (see below), whose sum is σ = 27981928904448. Its totient is φ = 12825050747784.
The previous prime is 20112011399999. The next prime is 20112011400011. The reversal of 20112011400003 is 30000411021102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 20112011400003 - 22 = 20112011399999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20112011400053) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 145739212975 + ... + 145739213112.
It is an arithmetic number, because the mean of its divisors is an integer number (3497741113056).
Almost surely, 220112011400003 is an apocalyptic number.
20112011400003 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
20112011400003 is a deficient number, since it is larger than the sum of its proper divisors (7869917504445).
20112011400003 is a wasteful number, since it uses less digits than its factorization.
20112011400003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 291478426113.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 20112011400003 its reverse (30000411021102), we get a palindrome (50112422421105).
The spelling of 20112011400003 in words is "twenty trillion, one hundred twelve billion, eleven million, four hundred thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •