Base | Representation |
---|---|
bin | 101101101110101011110010… |
… | …110110101011100110011011 |
3 | 222101002220102110001210100111 |
4 | 231232223302312223212123 |
5 | 202330123144013220011 |
6 | 1551425203402145151 |
7 | 60235312240023613 |
oct | 5556536266534633 |
9 | 871086373053314 |
10 | 201120213023131 |
11 | 590a0670070836 |
12 | 1a6825404b21b7 |
13 | 882b72990896c |
14 | 37943ad7c5a43 |
15 | 183b8e9339121 |
hex | b6eaf2dab99b |
201120213023131 has 2 divisors, whose sum is σ = 201120213023132. Its totient is φ = 201120213023130.
The previous prime is 201120213023129. The next prime is 201120213023167. The reversal of 201120213023131 is 131320312021102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201120213023131 - 21 = 201120213023129 is a prime.
It is a super-2 number, since 2×2011202130231312 (a number of 29 digits) contains 22 as substring.
Together with 201120213023129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (201120213021131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100560106511565 + 100560106511566.
It is an arithmetic number, because the mean of its divisors is an integer number (100560106511566).
Almost surely, 2201120213023131 is an apocalyptic number.
201120213023131 is a deficient number, since it is larger than the sum of its proper divisors (1).
201120213023131 is an equidigital number, since it uses as much as digits as its factorization.
201120213023131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 201120213023131 its reverse (131320312021102), we get a palindrome (332440525044233).
The spelling of 201120213023131 in words is "two hundred one trillion, one hundred twenty billion, two hundred thirteen million, twenty-three thousand, one hundred thirty-one".
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