Base | Representation |
---|---|
bin | 11101010001001011011… |
… | …111010110001011100111 |
3 | 21010021112201212111112021 |
4 | 131101023133112023213 |
5 | 230423131131444142 |
6 | 4135552243204011 |
7 | 265212111100306 |
oct | 35211337261347 |
9 | 7107481774467 |
10 | 2011311203047 |
11 | 705aa0815083 |
12 | 285980076607 |
13 | 117886aacb23 |
14 | 6d4c2c0c43d |
15 | 374bb040267 |
hex | 1d44b7d62e7 |
2011311203047 has 2 divisors, whose sum is σ = 2011311203048. Its totient is φ = 2011311203046.
The previous prime is 2011311203029. The next prime is 2011311203101. The reversal of 2011311203047 is 7403021131102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011311203047 - 27 = 2011311202919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011311213047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005655601523 + 1005655601524.
It is an arithmetic number, because the mean of its divisors is an integer number (1005655601524).
Almost surely, 22011311203047 is an apocalyptic number.
2011311203047 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011311203047 is an equidigital number, since it uses as much as digits as its factorization.
2011311203047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 2011311203047 its reverse (7403021131102), we get a palindrome (9414332334149).
The spelling of 2011311203047 in words is "two trillion, eleven billion, three hundred eleven million, two hundred three thousand, forty-seven".
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