Search a number
-
+
2011335130501 is a prime number
BaseRepresentation
bin11101010001001100111…
…010100111110110000101
321010021121101220010211021
4131101030322213312011
5230423203243134001
64135554500111141
7265212521344534
oct35211472476605
97107541803737
102011335130501
11706003278134
122859880954b1
1311788ba39a98
146d4c607a31b
15374bd1b9ba1
hex1d44cea7d85

2011335130501 has 2 divisors, whose sum is σ = 2011335130502. Its totient is φ = 2011335130500.

The previous prime is 2011335130393. The next prime is 2011335130537. The reversal of 2011335130501 is 1050315331102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1932725550625 + 78609579876 = 1390225^2 + 280374^2 .

It is a cyclic number.

It is not a de Polignac number, because 2011335130501 - 219 = 2011334606213 is a prime.

It is a super-2 number, since 2×20113351305012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2011335130591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005667565250 + 1005667565251.

It is an arithmetic number, because the mean of its divisors is an integer number (1005667565251).

Almost surely, 22011335130501 is an apocalyptic number.

It is an amenable number.

2011335130501 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011335130501 is an equidigital number, since it uses as much as digits as its factorization.

2011335130501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350, while the sum is 25.

The spelling of 2011335130501 in words is "two trillion, eleven billion, three hundred thirty-five million, one hundred thirty thousand, five hundred one".