Base | Representation |
---|---|
bin | 111011111100010… |
… | …1010101010001001 |
3 | 12012011200211120121 |
4 | 1313320222222021 |
5 | 13104400442442 |
6 | 531330023241 |
7 | 100562065132 |
oct | 16770525211 |
9 | 5164624517 |
10 | 2011343497 |
11 | 942395159 |
12 | 481717b21 |
13 | 2609195a7 |
14 | 1511acc89 |
15 | bb8a3967 |
hex | 77e2aa89 |
2011343497 has 2 divisors, whose sum is σ = 2011343498. Its totient is φ = 2011343496.
The previous prime is 2011343489. The next prime is 2011343501. The reversal of 2011343497 is 7943431102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1703130361 + 308213136 = 41269^2 + 17556^2 .
It is a cyclic number.
It is not a de Polignac number, because 2011343497 - 23 = 2011343489 is a prime.
It is not a weakly prime, because it can be changed into another prime (2011343407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005671748 + 1005671749.
It is an arithmetic number, because the mean of its divisors is an integer number (1005671749).
Almost surely, 22011343497 is an apocalyptic number.
It is an amenable number.
2011343497 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011343497 is an equidigital number, since it uses as much as digits as its factorization.
2011343497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 34.
The square root of 2011343497 is about 44848.0043814661. The cubic root of 2011343497 is about 1262.2985457995.
Adding to 2011343497 its reverse (7943431102), we get a palindrome (9954774599).
The spelling of 2011343497 in words is "two billion, eleven million, three hundred forty-three thousand, four hundred ninety-seven".
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