Base | Representation |
---|---|
bin | 10010101110111010… |
… | …011001001111010001 |
3 | 1220220210211000200122 |
4 | 102232322121033101 |
5 | 312143242144442 |
6 | 13123533400025 |
7 | 1311311454014 |
oct | 225672311721 |
9 | 56823730618 |
10 | 20114412497 |
11 | 8592074903 |
12 | 3a94339015 |
13 | 1b872c653a |
14 | d8b58937b |
15 | 7cad1add2 |
hex | 4aee993d1 |
20114412497 has 2 divisors, whose sum is σ = 20114412498. Its totient is φ = 20114412496.
The previous prime is 20114412463. The next prime is 20114412517. The reversal of 20114412497 is 79421441102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18486209296 + 1628203201 = 135964^2 + 40351^2 .
It is a cyclic number.
It is not a de Polignac number, because 20114412497 - 212 = 20114408401 is a prime.
It is not a weakly prime, because it can be changed into another prime (20114414497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10057206248 + 10057206249.
It is an arithmetic number, because the mean of its divisors is an integer number (10057206249).
Almost surely, 220114412497 is an apocalyptic number.
It is an amenable number.
20114412497 is a deficient number, since it is larger than the sum of its proper divisors (1).
20114412497 is an equidigital number, since it uses as much as digits as its factorization.
20114412497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 35.
Adding to 20114412497 its reverse (79421441102), we get a palindrome (99535853599).
The spelling of 20114412497 in words is "twenty billion, one hundred fourteen million, four hundred twelve thousand, four hundred ninety-seven".
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