Base | Representation |
---|---|
bin | 1011101101010100011… |
… | …1111110111101111111 |
3 | 201020012002011210102012 |
4 | 2323111013332331333 |
5 | 11243420344314201 |
6 | 232223200521435 |
7 | 20350352641112 |
oct | 2732507767577 |
9 | 636162153365 |
10 | 201144135551 |
11 | 78339691177 |
12 | 32b9692027b |
13 | 15c77383b68 |
14 | 9a4202c579 |
15 | 5373b275bb |
hex | 2ed51fef7f |
201144135551 has 4 divisors (see below), whose sum is σ = 201265089792. Its totient is φ = 201023181312.
The previous prime is 201144135481. The next prime is 201144135601. The reversal of 201144135551 is 155531441102.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 155531441102 = 2 ⋅77765720551.
It is a cyclic number.
It is not a de Polignac number, because 201144135551 - 230 = 200070393727 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201144138551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60474626 + ... + 60477951.
It is an arithmetic number, because the mean of its divisors is an integer number (50316272448).
Almost surely, 2201144135551 is an apocalyptic number.
201144135551 is a deficient number, since it is larger than the sum of its proper divisors (120954241).
201144135551 is a wasteful number, since it uses less digits than its factorization.
201144135551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120954240.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 201144135551 its reverse (155531441102), we get a palindrome (356675576653).
The spelling of 201144135551 in words is "two hundred one billion, one hundred forty-four million, one hundred thirty-five thousand, five hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •