Base | Representation |
---|---|
bin | 1001001001011110010011… |
… | …00010111011001111010111 |
3 | 2122020010202022222112220102 |
4 | 10210233021202323033113 |
5 | 10114043012041120002 |
6 | 110441253535324315 |
7 | 4144245623034263 |
oct | 444571142731727 |
9 | 78203668875812 |
10 | 20116713223127 |
11 | 64564a519a034 |
12 | 230a90668069b |
13 | b2bcc8568701 |
14 | 4d7922c6b0a3 |
15 | 24d4364eba02 |
hex | 124bc98bb3d7 |
20116713223127 has 2 divisors, whose sum is σ = 20116713223128. Its totient is φ = 20116713223126.
The previous prime is 20116713223091. The next prime is 20116713223169. The reversal of 20116713223127 is 72132231761102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20116713223127 - 240 = 19017201595351 is a prime.
It is a super-3 number, since 3×201167132231273 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20116713223627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10058356611563 + 10058356611564.
It is an arithmetic number, because the mean of its divisors is an integer number (10058356611564).
Almost surely, 220116713223127 is an apocalyptic number.
20116713223127 is a deficient number, since it is larger than the sum of its proper divisors (1).
20116713223127 is an equidigital number, since it uses as much as digits as its factorization.
20116713223127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 42336, while the sum is 38.
Adding to 20116713223127 its reverse (72132231761102), we get a palindrome (92248944984229).
The spelling of 20116713223127 in words is "twenty trillion, one hundred sixteen billion, seven hundred thirteen million, two hundred twenty-three thousand, one hundred twenty-seven".
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