Base | Representation |
---|---|
bin | 1001001001011110011000… |
… | …00100000110110001010111 |
3 | 2122020010212021111012022201 |
4 | 10210233030010012301113 |
5 | 10114043103400204133 |
6 | 110441302045105331 |
7 | 4144246645133206 |
oct | 444571404066127 |
9 | 78203767435281 |
10 | 20116755475543 |
11 | 6456517028991 |
12 | 230a918858247 |
13 | b2c00424053c |
14 | 4d792870923d |
15 | 24d43a095d7d |
hex | 124bcc106c57 |
20116755475543 has 2 divisors, whose sum is σ = 20116755475544. Its totient is φ = 20116755475542.
The previous prime is 20116755475513. The next prime is 20116755475549. The reversal of 20116755475543 is 34557455761102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20116755475543 - 225 = 20116721921111 is a prime.
It is a super-2 number, since 2×201167554755432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20116755475549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10058377737771 + 10058377737772.
It is an arithmetic number, because the mean of its divisors is an integer number (10058377737772).
Almost surely, 220116755475543 is an apocalyptic number.
20116755475543 is a deficient number, since it is larger than the sum of its proper divisors (1).
20116755475543 is an equidigital number, since it uses as much as digits as its factorization.
20116755475543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17640000, while the sum is 55.
The spelling of 20116755475543 in words is "twenty trillion, one hundred sixteen billion, seven hundred fifty-five million, four hundred seventy-five thousand, five hundred forty-three".
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