Base | Representation |
---|---|
bin | 1001001001011110011000… |
… | …11010011000011010100111 |
3 | 2122020010212200110212112021 |
4 | 10210233030122120122213 |
5 | 10114043111344034413 |
6 | 110441302414204011 |
7 | 4144250045563624 |
oct | 444571432303247 |
9 | 78203780425467 |
10 | 20116761314983 |
11 | 645651a357173 |
12 | 230a91a7b3607 |
13 | b2c005506428 |
14 | 4d79293c934b |
15 | 24d43a84b18d |
hex | 124bcc6986a7 |
20116761314983 has 2 divisors, whose sum is σ = 20116761314984. Its totient is φ = 20116761314982.
The previous prime is 20116761314929. The next prime is 20116761315017. The reversal of 20116761314983 is 38941316761102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20116761314983 - 225 = 20116727760551 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20116761314983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20116761314383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10058380657491 + 10058380657492.
It is an arithmetic number, because the mean of its divisors is an integer number (10058380657492).
Almost surely, 220116761314983 is an apocalyptic number.
20116761314983 is a deficient number, since it is larger than the sum of its proper divisors (1).
20116761314983 is an equidigital number, since it uses as much as digits as its factorization.
20116761314983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1306368, while the sum is 52.
The spelling of 20116761314983 in words is "twenty trillion, one hundred sixteen billion, seven hundred sixty-one million, three hundred fourteen thousand, nine hundred eighty-three".
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