Base | Representation |
---|---|
bin | 101101101111110110000111… |
… | …110001111101001100100111 |
3 | 222101101112102101212010111122 |
4 | 231233312013301331030213 |
5 | 202332430120334012444 |
6 | 1551530002540124155 |
7 | 60244136040446126 |
oct | 5557660761751447 |
9 | 871345371763448 |
10 | 201200021000999 |
11 | 591214a4643839 |
12 | 1a695ab3b3665b |
13 | 883610801a7c7 |
14 | 37981c0c57abd |
15 | 183da1aa274ee |
hex | b6fd87c7d327 |
201200021000999 has 2 divisors, whose sum is σ = 201200021001000. Its totient is φ = 201200021000998.
The previous prime is 201200021000969. The next prime is 201200021001011. The reversal of 201200021000999 is 999000120002102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201200021000999 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201200021000969) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100600010500499 + 100600010500500.
It is an arithmetic number, because the mean of its divisors is an integer number (100600010500500).
Almost surely, 2201200021000999 is an apocalyptic number.
201200021000999 is a deficient number, since it is larger than the sum of its proper divisors (1).
201200021000999 is an equidigital number, since it uses as much as digits as its factorization.
201200021000999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 35.
The spelling of 201200021000999 in words is "two hundred one trillion, two hundred billion, twenty-one million, nine hundred ninety-nine", and thus it is an aban number.
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