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201200101153 is a prime number
BaseRepresentation
bin1011101101100001110…
…1011110011100100001
3201020022222111010210021
42323120131132130201
511244024211214103
6232232520233441
720351632433122
oct2733035363441
9636288433707
10201200101153
1178368236a37
1232bb160b881
1315c85b4a6bc
149a4963a049
1553789cebbd
hex2ed875e721

201200101153 has 2 divisors, whose sum is σ = 201200101154. Its totient is φ = 201200101152.

The previous prime is 201200101021. The next prime is 201200101169. The reversal of 201200101153 is 351101002102.

It is an a-pointer prime, because the next prime (201200101169) can be obtained adding 201200101153 to its sum of digits (16).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 196609767649 + 4590333504 = 443407^2 + 67752^2 .

It is a cyclic number.

It is not a de Polignac number, because 201200101153 - 29 = 201200100641 is a prime.

It is not a weakly prime, because it can be changed into another prime (201200101183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100600050576 + 100600050577.

It is an arithmetic number, because the mean of its divisors is an integer number (100600050577).

Almost surely, 2201200101153 is an apocalyptic number.

It is an amenable number.

201200101153 is a deficient number, since it is larger than the sum of its proper divisors (1).

201200101153 is an equidigital number, since it uses as much as digits as its factorization.

201200101153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 201200101153 its reverse (351101002102), we get a palindrome (552301103255).

The spelling of 201200101153 in words is "two hundred one billion, two hundred million, one hundred one thousand, one hundred fifty-three".