| Base | Representation |
|---|---|
| bin | 101101101111110110001101… |
| … | …001010011101110011100100 |
| 3 | 222101101112122200210102001020 |
| 4 | 231233312031022131303210 |
| 5 | 202332430311443441400 |
| 6 | 1551530015523531140 |
| 7 | 60244141215205605 |
| oct | 5557661512356344 |
| 9 | 871345580712036 |
| 10 | 201200111312100 |
| 11 | 5912154061790a |
| 12 | 1a695b1a229ab0 |
| 13 | 883612094b224 |
| 14 | 37981ccc45dac |
| 15 | 183da239162a0 |
| hex | b6fd8d29dce4 |
201200111312100 has 288 divisors, whose sum is σ = 600583715182080. Its totient is φ = 51973346304000.
The previous prime is 201200111312069. The next prime is 201200111312107. The reversal of 201200111312100 is 1213111002102.
201200111312100 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 201200111312100.
It is not an unprimeable number, because it can be changed into a prime (201200111312107) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 976553896 + ... + 976759904.
It is an arithmetic number, because the mean of its divisors is an integer number (2085360122160).
Almost surely, 2201200111312100 is an apocalyptic number.
201200111312100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 201200111312100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (300291857591040).
201200111312100 is an abundant number, since it is smaller than the sum of its proper divisors (399383603869980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201200111312100 is a wasteful number, since it uses less digits than its factorization.
201200111312100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206631 (or 206624 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 201200111312100 its reverse (1213111002102), we get a palindrome (202413222314202).
The spelling of 201200111312100 in words is "two hundred one trillion, two hundred billion, one hundred eleven million, three hundred twelve thousand, one hundred".
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