Search a number
-
+
2012010043313 is a prime number
BaseRepresentation
bin11101010001110101001…
…001001101011110110001
321010100100102212021011002
4131101311021031132301
5230431044032341223
64140145445531345
7265235325121424
oct35216511153661
97110312767132
102012010043313
1170631a242116
12285b36113b55
1311796880438a
146d54b9639bb
153750c583e28
hex1d47524d7b1

2012010043313 has 2 divisors, whose sum is σ = 2012010043314. Its totient is φ = 2012010043312.

The previous prime is 2012010043301. The next prime is 2012010043423. The reversal of 2012010043313 is 3133400102102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1323528299809 + 688481743504 = 1150447^2 + 829748^2 .

It is a cyclic number.

It is not a de Polignac number, because 2012010043313 - 212 = 2012010039217 is a prime.

It is not a weakly prime, because it can be changed into another prime (2012010043513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006005021656 + 1006005021657.

It is an arithmetic number, because the mean of its divisors is an integer number (1006005021657).

Almost surely, 22012010043313 is an apocalyptic number.

It is an amenable number.

2012010043313 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012010043313 is an equidigital number, since it uses as much as digits as its factorization.

2012010043313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 2012010043313 its reverse (3133400102102), we get a palindrome (5145410145415).

The spelling of 2012010043313 in words is "two trillion, twelve billion, ten million, forty-three thousand, three hundred thirteen".