Base | Representation |
---|---|
bin | 11101010001110101001… |
… | …001001101100000011111 |
3 | 21010100100102212021022011 |
4 | 131101311021031200133 |
5 | 230431044032342143 |
6 | 4140145445532051 |
7 | 265235325121642 |
oct | 35216511154037 |
9 | 7110312767264 |
10 | 2012010043423 |
11 | 70631a242206 |
12 | 285b36114027 |
13 | 117968804443 |
14 | 6d54b963a59 |
15 | 3750c583e9d |
hex | 1d47524d81f |
2012010043423 has 2 divisors, whose sum is σ = 2012010043424. Its totient is φ = 2012010043422.
The previous prime is 2012010043313. The next prime is 2012010043447. The reversal of 2012010043423 is 3243400102102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2012010043423 - 221 = 2012007946271 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2012010043394 and 2012010043403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012010043523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006005021711 + 1006005021712.
It is an arithmetic number, because the mean of its divisors is an integer number (1006005021712).
Almost surely, 22012010043423 is an apocalyptic number.
2012010043423 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012010043423 is an equidigital number, since it uses as much as digits as its factorization.
2012010043423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 2012010043423 its reverse (3243400102102), we get a palindrome (5255410145525).
The spelling of 2012010043423 in words is "two trillion, twelve billion, ten million, forty-three thousand, four hundred twenty-three".
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