Base | Representation |
---|---|
bin | 1001001001100100101000… |
… | …01100110100010000001111 |
3 | 2122020110112021122101100221 |
4 | 10210302110030310100033 |
5 | 10114121442434432231 |
6 | 110443015152532211 |
7 | 4144426106263552 |
oct | 444622414642017 |
9 | 78213467571327 |
10 | 20120113202191 |
11 | 645798a410692 |
12 | 230b4b5251067 |
13 | b2c41aa84b42 |
14 | 4d7b66630699 |
15 | 24d584c4cd11 |
hex | 124c9433440f |
20120113202191 has 2 divisors, whose sum is σ = 20120113202192. Its totient is φ = 20120113202190.
The previous prime is 20120113202153. The next prime is 20120113202221. The reversal of 20120113202191 is 19120231102102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20120113202191 - 235 = 20085753463823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20120113202131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060056601095 + 10060056601096.
It is an arithmetic number, because the mean of its divisors is an integer number (10060056601096).
Almost surely, 220120113202191 is an apocalyptic number.
20120113202191 is a deficient number, since it is larger than the sum of its proper divisors (1).
20120113202191 is an equidigital number, since it uses as much as digits as its factorization.
20120113202191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 20120113202191 its reverse (19120231102102), we get a palindrome (39240344304293).
It can be divided in two parts, 20120 and 113202191, that added together give a palindrome (113222311).
The spelling of 20120113202191 in words is "twenty trillion, one hundred twenty billion, one hundred thirteen million, two hundred two thousand, one hundred ninety-one".
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