Base | Representation |
---|---|
bin | 11101010001110101001… |
… | …110100101010000001111 |
3 | 21010100100112111210200201 |
4 | 131101311032211100033 |
5 | 230431044412421112 |
6 | 4140145540034331 |
7 | 265235343104566 |
oct | 35216516452017 |
9 | 7110315453621 |
10 | 2012011451407 |
11 | 706320014031 |
12 | 285b366929a7 |
13 | 117968ba8279 |
14 | 6d54bc0cbdd |
15 | 3750c761257 |
hex | 1d4753a540f |
2012011451407 has 2 divisors, whose sum is σ = 2012011451408. Its totient is φ = 2012011451406.
The previous prime is 2012011451389. The next prime is 2012011451453. The reversal of 2012011451407 is 7041541102102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2012011451407 - 211 = 2012011449359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012011451477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006005725703 + 1006005725704.
It is an arithmetic number, because the mean of its divisors is an integer number (1006005725704).
Almost surely, 22012011451407 is an apocalyptic number.
2012011451407 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012011451407 is an equidigital number, since it uses as much as digits as its factorization.
2012011451407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2240, while the sum is 28.
Adding to 2012011451407 its reverse (7041541102102), we get a palindrome (9053552553509).
The spelling of 2012011451407 in words is "two trillion, twelve billion, eleven million, four hundred fifty-one thousand, four hundred seven".
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