Base | Representation |
---|---|
bin | 11101010001110101010… |
… | …000101110010111110001 |
3 | 21010100100120120100002222 |
4 | 131101311100232113301 |
5 | 230431100033404131 |
6 | 4140150000050425 |
7 | 265235350634162 |
oct | 35216520562761 |
9 | 7110316510088 |
10 | 2012012013041 |
11 | 706320367a98 |
12 | 285b36903a15 |
13 | 117969043ab4 |
14 | 6d54bd17769 |
15 | 3750c82287b |
hex | 1d47542e5f1 |
2012012013041 has 2 divisors, whose sum is σ = 2012012013042. Its totient is φ = 2012012013040.
The previous prime is 2012012013029. The next prime is 2012012013061. The reversal of 2012012013041 is 1403102102102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1834951996816 + 177060016225 = 1354604^2 + 420785^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012012013041 - 230 = 2010938271217 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (2012012013061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006006006520 + 1006006006521.
It is an arithmetic number, because the mean of its divisors is an integer number (1006006006521).
Almost surely, 22012012013041 is an apocalyptic number.
It is an amenable number.
2012012013041 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012012013041 is an equidigital number, since it uses as much as digits as its factorization.
2012012013041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2012012013041 its reverse (1403102102102), we get a palindrome (3415114115143).
The spelling of 2012012013041 in words is "two trillion, twelve billion, twelve million, thirteen thousand, forty-one".
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