Base | Representation |
---|---|
bin | 11101010001110101010… |
… | …000110000010101110111 |
3 | 21010100100120120202011212 |
4 | 131101311100300111313 |
5 | 230431100034133421 |
6 | 4140150000152035 |
7 | 265235350666541 |
oct | 35216520602567 |
9 | 7110316522155 |
10 | 2012012021111 |
11 | 706320373064 |
12 | 285b3690861b |
13 | 117969047681 |
14 | 6d54bd1a691 |
15 | 3750c824e5b |
hex | 1d475430577 |
2012012021111 has 2 divisors, whose sum is σ = 2012012021112. Its totient is φ = 2012012021110.
The previous prime is 2012012021099. The next prime is 2012012021119. The reversal of 2012012021111 is 1111202102102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2012012021111 - 210 = 2012012020087 is a prime.
It is a super-2 number, since 2×20120120211112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012012021119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006006010555 + 1006006010556.
It is an arithmetic number, because the mean of its divisors is an integer number (1006006010556).
Almost surely, 22012012021111 is an apocalyptic number.
2012012021111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012012021111 is an equidigital number, since it uses as much as digits as its factorization.
2012012021111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 2012012021111 its reverse (1111202102102), we get a palindrome (3123214123213).
The spelling of 2012012021111 in words is "two trillion, twelve billion, twelve million, twenty-one thousand, one hundred eleven".
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