Base | Representation |
---|---|
bin | 11101010001110101010… |
… | …001000110100100000101 |
3 | 21010100100120202101001001 |
4 | 131101311101012210011 |
5 | 230431100100042013 |
6 | 4140150002133301 |
7 | 265235351526112 |
oct | 35216521064405 |
9 | 7110316671031 |
10 | 2012012112133 |
11 | 706320425491 |
12 | 285b36951231 |
13 | 117969079c2a |
14 | 6d54bd41909 |
15 | 3750c841ddd |
hex | 1d475446905 |
2012012112133 has 2 divisors, whose sum is σ = 2012012112134. Its totient is φ = 2012012112132.
The previous prime is 2012012112127. The next prime is 2012012112161. The reversal of 2012012112133 is 3312112102102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1977617813284 + 34394298849 = 1406278^2 + 185457^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012012112133 - 217 = 2012011981061 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2012012112133.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012012112113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006006056066 + 1006006056067.
It is an arithmetic number, because the mean of its divisors is an integer number (1006006056067).
Almost surely, 22012012112133 is an apocalyptic number.
It is an amenable number.
2012012112133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012012112133 is an equidigital number, since it uses as much as digits as its factorization.
2012012112133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2012012112133 its reverse (3312112102102), we get a palindrome (5324124214235).
The spelling of 2012012112133 in words is "two trillion, twelve billion, twelve million, one hundred twelve thousand, one hundred thirty-three".
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