Base | Representation |
---|---|
bin | 1001001001100100110010… |
… | …11100001010011010100011 |
3 | 2122020110202102001121212021 |
4 | 10210302121130022122203 |
5 | 10114122132441024303 |
6 | 110443032013042311 |
7 | 4144431224430214 |
oct | 444623134123243 |
9 | 78213672047767 |
10 | 20120201111203 |
11 | 6457a24aa3a66 |
12 | 230b51a786397 |
13 | b2c4330540cb |
14 | 4d7b7419540b |
15 | 24d58c814ebd |
hex | 124c9970a6a3 |
20120201111203 has 8 divisors (see below), whose sum is σ = 21350839795200. Its totient is φ = 18919216371528.
The previous prime is 20120201111191. The next prime is 20120201111243. The reversal of 20120201111203 is 30211110202102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20120201111203 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20120201111243) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7413484683 + ... + 7413487396.
It is an arithmetic number, because the mean of its divisors is an integer number (2668854974400).
Almost surely, 220120201111203 is an apocalyptic number.
20120201111203 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
20120201111203 is a deficient number, since it is larger than the sum of its proper divisors (1230638683997).
20120201111203 is a wasteful number, since it uses less digits than its factorization.
20120201111203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14826972161.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 20120201111203 its reverse (30211110202102), we get a palindrome (50331311313305).
The spelling of 20120201111203 in words is "twenty trillion, one hundred twenty billion, two hundred one million, one hundred eleven thousand, two hundred three".
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