Search a number
-
+
201202202112000 = 212353233956003
BaseRepresentation
bin101101101111111000001001…
…110010001111000000000000
3222101101202001102000001022120
4231233320021302033000000
5202332444102220041000
61551531003213004240
760244244063544255
oct5557701162170000
9871352042001276
10201202202112000
1159122413841811
121a696402483680
138836394b6762b
14379834a7b942c
15183dae72626a0
hexb6fe09c8f000

201202202112000 has 416 divisors, whose sum is σ = 669817392042240. Its totient is φ = 53630024089600.

The previous prime is 201202202111951. The next prime is 201202202112083. The reversal of 201202202112000 is 211202202102.

It is a super-2 number, since 2×2012022021120002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3592675999 + ... + 3592732001.

It is an arithmetic number, because the mean of its divisors is an integer number (1610137961640).

Almost surely, 2201202202112000 is an apocalyptic number.

201202202112000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201202202112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (334908696021120).

201202202112000 is an abundant number, since it is smaller than the sum of its proper divisors (468615189930240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201202202112000 is an equidigital number, since it uses as much as digits as its factorization.

201202202112000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58384 (or 58352 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 15.

Adding to 201202202112000 its reverse (211202202102), we get a palindrome (201413404314102).

It can be divided in two parts, 201202 and 202112000, that added together give a palindrome (202313202).

The spelling of 201202202112000 in words is "two hundred one trillion, two hundred two billion, two hundred two million, one hundred twelve thousand".