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201203103112211 is a prime number
BaseRepresentation
bin101101101111111000111111…
…011111010001110000010011
3222101101211101012101121020202
4231233320333133101300103
5202333002423344042321
61551531232440325415
760244305314120114
oct5557707737216023
9871354335347222
10201203103112211
1159122836397592
121a69661417386b
1388364a9721355
1437983d431620b
15183db4b3da70b
hexb6fe3f7d1c13

201203103112211 has 2 divisors, whose sum is σ = 201203103112212. Its totient is φ = 201203103112210.

The previous prime is 201203103112093. The next prime is 201203103112213. The reversal of 201203103112211 is 112211301302102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 201203103112211 - 218 = 201203102850067 is a prime.

Together with 201203103112213, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (201203103112213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100601551556105 + 100601551556106.

It is an arithmetic number, because the mean of its divisors is an integer number (100601551556106).

Almost surely, 2201203103112211 is an apocalyptic number.

201203103112211 is a deficient number, since it is larger than the sum of its proper divisors (1).

201203103112211 is an equidigital number, since it uses as much as digits as its factorization.

201203103112211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 201203103112211 its reverse (112211301302102), we get a palindrome (313414404414313).

The spelling of 201203103112211 in words is "two hundred one trillion, two hundred three billion, one hundred three million, one hundred twelve thousand, two hundred eleven".